Question

The radius of the Earth, re, is about 6.38 × 106 meters, and the mass of the Earth is 5.98 × 1024 kilograms. Calculate the gravitational field strength on the surface of the Earth.

Answer 1

The gravitational field strength on the surface of the Earth is 9.81 meters per second squared (m/s²).

Step-by-step explanation:

The gravitational field strength on the surface of the Earth can be calculated using Newton's law of universal gravitation:

`g=(GxM)/(r^2)`

Where:|

`g` is the gravitational field strength,

`G` is the gravitational constant
`(G=6.67430x10^(-11) m^3kg^-1s^(-2) ),`

`M` is the mass of the Earth,

`r` is the radius of the Earth.

Substituting the given values:

`g=((6.67430x10^(-11) m^3kg^(-1)s^(-2) )x(5.98x10^(24)kg) )/((6.38x10^6m)^2)`

Calculating this expression will give us the gravitational field strength on the surface of the Earth. Let's calculate it:


`g=((6.67430x10^(-11) m^3kg^(-1)s^(-2) )x(5.98x10^(24)kg) )/((6.38x10^6m)^2)=9.81 m/s^2`