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AABC is a right triangle. m2A = 32° mzB = 90°; AC = 9 and AB-5. Choose the expression used to find BC?

Select one:
O a.
O b.
c.
d.
9
tan58°
9
sin32º
5 cos 58%
5 tan 32°

AABC is a right triangle. m2A = 32° mzB = 90°; AC = 9 and AB-5. Choose the expression-example-1

1 Answer

4 votes

Answer:

9 sin 32º

Explanation:

The expression used to find BC in this scenario is:

a. 9 sin 32º

In a right triangle, the side opposite the angle is given by the length of the hypotenuse multiplied by the sine of the angle. In this case, BC is the side opposite angle A, so BC = AB * sin(A). Given AB = 5 and angle A = 32º, the expression becomes 5 * sin(32º), which simplifies to 9 sin 32º.

User Masoud Dadashi
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