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Express as a product
4sin(a/2)*cos(a/2)*cos3a+sin2a

1 Answer

3 votes

Explanation:

To express the given expression as a product, we can simplify it using trigonometric identities.

Recall the following trigonometric identities:

sin(2a) = 2sin(a)cos(a)

cos(3a) = 4cos^3(a) - 3cos(a)

Using these identities, we can rewrite the expression as follows:

4sin(a/2)cos(a/2)cos(3a) + sin(2a)

= 4sin(a/2)cos(a/2)(4cos^3(a) - 3cos(a)) + 2sin(a)cos(a)

= 16sin(a/2)cos(a/2)cos^3(a) - 12sin(a/2)cos(a/2)cos(a) + 2sin(a)cos(a)

= 2sin(a/2)cos(a/2)(8cos^3(a) - 6cos(a)) + 2sin(a)cos(a)

= 2sin(a/2)cos(a/2)(8cos^3(a) - 6cos(a) + sin(a))

Therefore, the given expression can be expressed as the product:

2sin(a/2)cos(a/2)(8cos^3(a) - 6cos(a) + sin(a))

User DJViking
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