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Find the derivative of the function y=sin x² with respect to x at x=√π.

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Answer: y'=-0.3924695585

Explanation: Find the first derivative of the function y then plug in x.

y'=2(sinx)(cosx)

y'=2(sin(√π))(cos(√π))

y'=2(.9797359)(-0.2002935)

y'=-0.3924695585

User Bagus Trihatmaja
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