Question

Ninety two passengers rode in a train coach seats cost 120 sleeper cost 285 total of the trip is 19,620 how many passengers purchased each ticket

Answer 1

40 passengers in the coach seats and 52 passengers in the sleeper seats.

Explanation:

Let's denote the number of coach passengers as "C" and the number of sleeper passengers as "S". We know from the problem statement that:

1. C + S = 92 (the total number of passengers)

2. 120C + 285S = 19,620 (the total cost of all tickets)

Now, we can solve these simultaneous equations.

One way to do this is by using substitution or elimination. However, the easiest way here might be to use the method of substitution, so let's solve the first equation for C:

C = 92 - S

Now we substitute C from the first equation into the second equation:

120(92 - S) + 285S = 19,620

11,040 - 120S + 285S = 19,620

165S = 8,580

S = 8,580 / 165

S = 52

Substitute S = 52 into the first equation to get C:

C = 92 - 52 = 40

So, there were 40 passengers in the coach seats and 52 passengers in the sleeper seats.