Question

Answer the following word problem. A T-Rex skeleton has height of about. 12 ft., width of about 6 ft.,

and a length of about 40 ft. Can the museum director fit a fully built T-Rex skeleton display inside a
large case that is 5 yards high, 3 yards wide and 13 yards what is the case in feet?

Answer 1

the fully built T-Rex skeleton display cannot fit inside the large case

Explanation:

compare the dimensions of the skeleton to the dimensions of the case.

Given:

T-Rex skeleton dimensions:

Height = 12 ft.

Width = 6 ft.

Length = 40 ft.

Case dimensions:

Height = 5 yards

Width = 3 yards

Length = 13 yards

To compare the dimensions, we need to convert the case dimensions from yards to feet, as the T-Rex skeleton dimensions are given in feet.

1 yard = 3 feet

Case dimensions in feet:

Height = 5 yards * 3 feet/yard = 15 feet

Width = 3 yards * 3 feet/yard = 9 feet

Length = 13 yards * 3 feet/yard = 39 feet

Now we can compare the dimensions of the T-Rex skeleton and the case:

T-Rex skeleton:

Height = 12 ft.

Width = 6 ft.

Length = 40 ft.

Case:

Height = 15 ft.

Width = 9 ft.

Length = 39 ft.

Based on the dimensions, we can see that the height of the T-Rex skeleton (12 ft.) is smaller than the height of the case (15 ft.). Similarly, the width of the T-Rex skeleton (6 ft.) is smaller than the width of the case (9 ft.). However, the length of the T-Rex skeleton (40 ft.) is larger than the length of the case (39 ft.).

Therefore, the fully built T-Rex skeleton display cannot fit inside the large case because the length of the skeleton exceeds the length of the case.