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Rewrite the quadratic function in vertex form and give the vertex
f(x)=2x^2-10x

User The Fool
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To rewrite the quadratic function f(x) = 2x^2 - 10x in vertex form, we need to complete the square. The vertex form of a quadratic function is given by f(x) = a(x - h)^2 + k, where (h, k) represents the vertex.

Let's complete the square:

f(x) = 2x^2 - 10x

= 2(x^2 - 5x)

To complete the square, we need to take half of the coefficient of the x-term (-5), square it, and add it inside the parentheses:

f(x) = 2(x^2 - 5x + (-5/2)^2) - 2(-5/2)^2

= 2(x^2 - 5x + 25/4) - 2(25/4)

= 2(x^2 - 5x + 25/4) - 25/2

Now we can rewrite the function in vertex form:

f(x) = 2(x - 5/2)^2 - 25/2

The vertex of the quadratic function is given by the coordinates (h, k), where h = 5/2 and k = -25/2. Therefore, the vertex of the function f(x) = 2x^2 - 10x is V(5/2, -25/2).

User Stuck
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