Question

Pls helppppp


solve the equation x^2 - 8c + 12 = 0 by factoring.

Answer 1

x=6, x=2

Explanation:

x^2 - 8x + 12 = 0

We want to know what two numbers multiply to 12 and add to -8.

-6 * -2 = 12

-6-2 = -8

(x-6)(x-2) =0

Using the zero product property, we can set each term equal to zero.

x-6 =0 x-2 =0

x=6, x=2

Answer 2

x=6 and x=2

Explanation:

Solve the given equation by factoring.

`x^2 - 8x + 12 = 0`

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To solve the equation by factoring, we need to find two numbers whose product is equal to the constant term, 12, and whose sum is equal to the coefficient of the linear term, -8x.

The factors of 12 are ==> 1, 2, 3, 4, 6, and 12

Considering the sum of the factors, we can see that 6 and 2 satisfy the condition,

6 + 2 = 8

We can now rewrite the equation.

`x^2 - 8x + 12 = 0\\\\\\\Longrightarrow (x-6)(x-2)=0`

Now, we can set each factor equal to zero and solve for x.

x - 6 = 0 -> x = 6

x - 2 = 0 -> x = 2

So, the solutions to the equation are x = 6 and x = 2.