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27. Paul is hosting a barbecue. He buys burgers that are sold in packs of 8 for £3.50 and burger buns that come in packs of 14, costing £0.95. Paul does not like waste and so wants to make sure that he has the same number of burgers and buns. He wants the least number possible. How much will he spend? (Assuming he buys at least 16 one!)​

User Idov
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Answer:

Let's first calculate the cost of one burger and one burger bun:

- One pack of 8 burgers costs £3.50, so each burger costs £3.50/8 = £0.44.

- One pack of 14 burger buns costs £0.95, so each bun costs £0.95/14 ≈ £0.0679, which we'll round to £0.07.

To have an equal number of burgers and buns, we need to find the common multiple of 8 and 14. The least common multiple of 8 and 14 is 56.

So, we need to buy 56/8 = 7 packs of burgers and 56/14 = 4 packs of burger buns. However, this means we'll have 7 leftover buns, so we need to buy an extra burger bun pack to have an equal number of buns and burgers.

Therefore, Paul needs to buy:

- 7 packs of burgers, costing 7 x £3.50 = £24.50

- 5 packs of burger buns, costing 5 x £0.95 = £4.75

The total cost would be £24.50 + £4.75 = £29.25.

Explanation:

User Martin Mihaylov
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