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Help please i’m so bad at algebra


multiply the complex numbers: (3+2i)(5-2i)

User Plamen
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2 Answers

2 votes

answer: 19 + 4i

Explanation:

hihi your problem is multiply complex numbers which goes onto polynomials and quadratics
okay anyways you can use the foil method !!

(3 + 2i)(5 - 2i) = 3 * 5 + 3 * (-2i) + 2i * 5 + 2i * (-2i)

simplify each term:

= 15 - 6i + 10i - 4i^2

note that i^2 is equal to -1:

= 15 - 6i + 10i - 4(-1)

= 15 - 6i + 10i + 4

combine like terms

= 19 + 4i

hope this helps !!

User Wandang
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8.7k points
5 votes

Answer:

The product of (3 + 2i)(5 - 2i) is 19 + 4i.

Explanation:

To multiply the complex numbers (3 + 2i)(5 - 2i), you can use the distributive property and the fact that the imaginary unit i is defined as the square root of -1.

Let's break it down step by step:

(3 + 2i)(5 - 2i)

Using the distributive property, we can multiply each term:

= 3(5) + 3(-2i) + 2i(5) + 2i(-2i)

Simplifying each term:

= 15 - 6i + 10i - 4i^2

Since i^2 is defined as -1:

= 15 - 6i + 10i - 4(-1)

= 15 - 6i + 10i + 4

Combining like terms:

= 19 + 4i

So, the product of (3 + 2i)(5 - 2i) is 19 + 4i.

User Morganesque
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8.2k points

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