Answer:
11) ~a can be derived using direct proof as follows:
1. ~c ⊃ (a ⊃ c) (Premise)
2. ~c (Premise)
3. Assume a (for indirect proof)
4. From 2 and 3, we have ~c ∧ a (conjunction introduction)
5. From 1 and 4, we have ~c (Modus Ponens)
6. From 2 and 5, we have a contradiction (¬ Intro)
7. Therefore, ¬a (¬ Intro)
13) ~x can be derived using direct proof as follows:
1. y ⊃ w (Premise)
2. ~w v ~y (Premise)
3. Assume x (for indirect proof)
4. y • z (From 3 and 1, Modus Ponens)
5. y (Simplification from 4)
6. ~w (Disjunctive Syllogism from 2 and 5)
7. ~y (Disjunctive Syllogism from 2 and 6)
8. From 7, we have ~y ∧ z (Conjunction introduction)
9. Therefore, ~x (¬ Intro)
12) ~k can be derived using direct proof as follows:
1. j ⊃ (k ⊃ l) (Premise)
2. l v j (Premise)
3. ~l (Premise)
4. Assume k (for indirect proof)
5. From 1 and 4, we have j ⊃ l (Modus Ponens)
6. From 2 and 3, we have j (Disjunctive Syllogism)
7. From 5 and 6, we have l (Modus Ponens)
8. From 3 and 7, we have a contradiction
9. Therefore, ~k (¬ Intro)
14) ~f can be derived using direct proof as follows:
1. (f ⊃ g) v h (Premise)
2. ~g (Premise)
3. ~h (Premise)
4. Assume f (for indirect proof)
5. f ⊃ g (Assumption 1 from 1)
6. g (Modus Ponens from 4 and 5)
7. From 2 and 6, we have a contradiction
8. Therefore, ~f (¬ Intro)
Step-by-step explanation: