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Which value of y makes the inqeuality 3y^2+2(y-5)>8 true​

User Pregmatch
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1 Answer

8 votes
Let us solve:
3y^2+3y-18>0
3y^2+9y-6y-18>0
3y(y+3)-6(y+3)>0
(3y-6)(y+3)>0
Thus, y=2 or -3 makes the given inequality true.
User Mbouzahir
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