Question

Find the first 4 terms of the sequence whose nth term are given as
Tn=2n²-3

Answer 1

The first four terms are -1, 5, 15, 29

Answer 2

Explanation:

To find the first four terms of the sequence given by the formula Tn = 2n² - 3, we substitute values of n from 1 to 4 into the formula.

For n = 1:

T1 = 2(1²) - 3

T1 = 2 - 3

T1 = -1

For n = 2:

T2 = 2(2²) - 3

T2 = 8 - 3

T2 = 5

For n = 3:

T3 = 2(3²) - 3

T3 = 18 - 3

T3 = 15

For n = 4:

T4 = 2(4²) - 3

T4 = 32 - 3

T4 = 29

Therefore, the first four terms of the sequence are: -1, 5, 15, 29.