Question

6. A balloon gathers -0.973 μC of charge as the wind blows it directly East through

Earth's magnetic field (BE = 5.01 x 10-5 T). If the magnetic force on the balloon is
8.11 x 10-10 N West.

what is the
velocity of the balloon?
a.-16.6 m/s
c. 8.44 m/s
b. 3.95 x 10-20 m/s
d. 16.6 m/s

Answer 1

Step-by-step explanation:

To determine the velocity of the balloon, we can use the formula for the magnetic force on a charged particle moving in a magnetic field:

F = qvB

Where:

F is the magnetic force,

q is the charge,

v is the velocity of the balloon, and

B is the magnetic field strength.

Given:

F = -8.11 x 10^-10 N (West)

q = -0.973 μC = -0.973 x 10^-6 C (the negative sign indicates the charge is negative)

B = 5.01 x 10^-5 T

We can rearrange the formula to solve for v:

v = F / (qB)

Substituting the given values:

v = (-8.11 x 10^-10 N) / (-0.973 x 10^-6 C * 5.01 x 10^-5 T)

v ≈ 16.6 m/s

Therefore, the velocity of the balloon is approximately 16.6 m/s. Option (d) is the correct answer.