To find the value of q that maximizes profit, we need to calculate the revenue and cost functions.
Revenue function:
R(q) = p*q = (110 - q)*q = 110q - q²
Cost function:
C(q) = q³ - 25q² + 2q + 3,000
Profit function:
P(q) = R(q) - C(q) = (110q - q²) - (q³ - 25q² + 2q + 3,000) = -q³ + 86q² + 108q - 3,000
To find the maximum profit, we need to take the derivative of the profit function and set it equal to zero:
P'(q) = -3q² + 172q + 108 = 0
Solving for q, we get q = 6 or q = 28.
To determine which value of q gives us the maximum profit, we need to take the second derivative of the profit function:
P''(q) = -6q + 172
When q = 6, P''(q) = 136 > 0, so the profit is