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Did I graph this equation right?
Equation: P=125+50w

Did I graph this equation right? Equation: P=125+50w-example-1
User Hvb
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1 Answer

3 votes

Answer:

yes

Explanation:

You want a graph of P = 125 +50W.

Slope-intercept form

The given equation is in slope-intercept form. The independent variable is W, and the dependent variable is P.

Axes assignments

Usually, the independent variable is graphed on the horizontal axis, which you have done.

The dependent variable is graphed on the vertical axis, which you have done.

The axes are correctly labeled and graduated.

Intercept

The "y-intercept" (P value) when the independent variable is zero is the constant in the equation, 125. You have correctly shown that on the graph.

Slope

The slope of the line is the coefficient of the independent variable (W) in the equation. You have correctly shown that P increases by 50 when W increases by 1.

Yes, you properly graphed the equation.

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User Hypenate
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