Question

Find the zero(s) of the rational expression below. (7x2+29x+24) /(5x2+ 19x+12)

Answer 1

x = -8/7

Explanation:

You want the zero(s) of the rational expression (7x²+29x+24) /(5x²+ 19x+12).

Zeros

The zeros will be the values of x that make the numerator of the simplified form of the expression be zero.

`(7x^2+29x+24)/(5x^2+19x+12)=((x+3)(7x+8))/((x+3)(5x+4))=(7x+8)/(5x+4)`

This is zero when ...

7x +8 = 0

x = -8/7 . . . . . . . subtract 8, divide by 7

The zero of the rational expression is x = -8/7.

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