Question

Question 1 A heterozygous yellow-seeded plant is crossed with a homozygous yellow seeded plant. i. ii. Question 2 Complete the punnet square and write the genotypic and phenotypic ration for the possible offsprings. (3 marks) Genotypic ration Phenotypic ration What is the probability of having a pure breeding green seeded offsprings (2 marks) What is the probability of having a yellow-seeded plant in F2 generation, when a true breeder from F1 is crossed with a non-true breeding yellow seeded plant? (2 marks)​

Answer 1

Step-by-step explanation:

To solve this problem, let's represent the heterozygous yellow-seeded plant as "Yy" and the homozygous yellow-seeded plant as "YY."

i. When crossing a heterozygous yellow-seeded plant (Yy) with a homozygous yellow-seeded plant (YY), we can set up a Punnett square to determine the possible offspring genotypes:

Y Y

y Yy Yy

y YY YY

ii. The genotypic ratio is 2:2 or 1:1 for the possible offspring genotypes: Yy and YY.

The phenotypic ratio is also 2:2 or 1:1 for the possible offspring phenotypes: yellow-seeded (YY and Yy).

Question 2:

To determine the probability of specific outcomes, we need additional information about the parental genotypes and their inheritance patterns. Please provide the genotypes of the true breeder from F1 and the non-true breeding yellow-seeded plant for a more accurate calculation.