Final answer:
When connected in series, a headlight and starter consume 56.52 W of power from a 12.0 V battery.
Step-by-step explanation:
When two resistors are connected in series, the total resistance is the sum of the individual resistances. In this case, the headlight has a resistance of 2.50 ohms and the starter has a resistance of 0.05 ohms.
To find the total resistance, we add the individual resistances: 2.50 ohms + 0.05 ohms = 2.55 ohms.
Now, we can use Ohm's law to calculate the total current flowing through the circuit. Ohm's law states that V = I * R, where V is the voltage, I is the current, and R is the resistance. Since the voltage is 12.0 V and the resistance is 2.55 ohms, we can rearrange the equation to solve for I: I = V / R. Plugging in the values, we get I = 12.0 V / 2.55 ohms = 4.71 A.
The power consumed by the circuit can be calculated using the formula P = I * V, where P is the power, I is the current, and V is the voltage. Plugging in the values, we get P = 4.71 A * 12.0 V = 56.52 W.