Question

Find the 16th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 1.

Answer 1

Answer: 136

Explanation:

a + ( 16 - 1 ) da + 15 d( 1 )

a = 1

d = 9

1 + 15 ( 9 )

1 + 135

136

Answer 2

a₁₆ = 136

Explanation:

the nth term of an arithmetic sequence is

`a_(n)` = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 1 and d = 9 , then

a₁₆ = 1 + (15 × 9) = 1 + 135 = 136