Question

A ball is thrown straight up 25 m/s, if it lands 10 seconds later, how high is the building?

Answer 1

Step-by-step explanation:

To determine the height of the building, we can use the kinematic equation for vertical motion:

h = v₀t + (1/2)gt²

Where:

h is the height of the building

v₀ is the initial velocity of the ball (25 m/s)

t is the time taken for the ball to reach the ground (10 seconds)

g is the acceleration due to gravity (approximately 9.8 m/s²)

Plugging in the values:

h = (25 m/s)(10 s) + (1/2)(9.8 m/s²)(10 s)²

h = 250 m + (1/2)(9.8 m/s²)(100 s²)

h = 250 m + 490 m

h = 740 m

Therefore, the height of the building is approximately 740 meters.

Hope it helps!! :))