Question

If the weight density of mud is y=10.36+0.18h, where "y" is in kN/m² and depth "h" is in meters, determine the pressure in kPa at a depth of 4.2m.

Answer 1

To find the pressure at a 4.2-meter depth in mud, use the equation y=10.36+0.18h, resulting in 11.116 kN/m², which is equivalent to 11.116 kPa.

Step-by-step explanation:

To determine the pressure at a depth of 4.2 meters in mud, we will use the given weight density equation y = 10.36 + 0.18h, where y is in kN/m² and the depth h is in meters. Plugging in the depth of 4.2 meters into the equation, we get y = 10.36 + 0.18(4.2). The calculated pressure y is the pressure in kilonewtons per square meter (kN/m²) at that depth.

The pressure in kilopascals (kPa) can be found by performing the following calculation: '

y = 10.36 + 0.18(4.2)
y = 10.36 + 0.756
y = 11.116 kN/m²

Since 1 kN/m² is equivalent to 1 kPa, the pressure at a depth of 4.2 meters in the mud is 11.116 kPa.