Answer:
The tangential force will be 42kN
Step-by-step explanation:
Cube side = 0.1m
the modulus of elasticity for Brass E=3.5×10^10 N/m²
displacement=1.2x10^-5 m
Area= A^2=0.1*0.1=0.01 m^2
P=Tangential force
= (displacement*Area*Elasticity)/L
=(1.2x10^-5*1.2x10^-5*3.5×10^10)/0.1
P=42kN