Question

A cube of brass* has sides of 0.10m. Determine the applied tangential force to displace the top of the block 1.2x10 m given that the modulus of elasticity for Brass (Ebrass) 3.5×10¹0 N/m² (10 marks) *The same principal can be used on rocks.

Answer 1

The tangential force will be 42kN

Step-by-step explanation:

Cube side = 0.1m

the modulus of elasticity for Brass E=3.5×10^10 N/m²

displacement=1.2x10^-5 m

Area= A^2=0.1*0.1=0.01 m^2

P=Tangential force

= (displacement*Area*Elasticity)/L

=(1.2x10^-5*1.2x10^-5*3.5×10^10)/0.1

P=42kN