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A certain organic acid has a ka of 5.01 × 10−4. what is its pka?

User Brian Hong
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Answer:

The pKa of an acid is equal to the negative logarithm of its Ka value.pKa = -log(Ka)Given that the Ka of the organic acid is 5.01 × 10−4.pKa = -log(5.01 × 10−4)pKa = 3.3

Therefore, the pKa of the organic acid is 3.3.

User Balun
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