Final answer:
The angular speed just before the centrifuge begins decelerating is approximately 1047.2 rad/s. The angular acceleration is approximately -10.72 rad/s². A point 8.13 cm from the center of the centrifuge travels approximately 473.53 m during the deceleration. The radial component of acceleration is approximately -0.87 m/s², and the tangential component of acceleration is also approximately -0.87 m/s².
Step-by-step explanation:
(a) To convert revolutions per minute (rpm) to radians per second (rad/s), we use the formula:
angular speed (rad/s) = (angular speed (rpm) * 2π) / 60
Given that the maximum rotation rate is 10,000 rpm, the angular speed just before it begins decelerating is:
angular speed = (10,000 * 2π) / 60 ≈ 1047.2 rad/s
(b) The angular acceleration can be calculated using the formula:
angular acceleration = (final angular speed - initial angular speed) / time
Since the centrifuge comes to rest, the final angular speed is 0, the initial angular speed is 1047.2 rad/s, and the time is 97.6 s, the angular acceleration is:
angular acceleration = (0 - 1047.2) / 97.6 ≈ -10.72 rad/s²
(c) The distance traveled by a point R = 8.13 cm from the center during the deceleration can be calculated using the formula:
distance = (initial angular speed * time) + (0.5 * angular acceleration * time^2)
Substituting the known values, we have:
distance = (1047.2 * 97.6) + (0.5 * -10.72 * (97.6)^2) ≈ 47352.65 cm ≈ 473.53 m
(d) The radial component of acceleration can be determined using the formula:
radial acceleration = (angular acceleration) * (distance from the center)
Substituting the known values, we have:
radial acceleration = (-10.72) * 0.0813 ≈ -0.87 m/s²
(e) The tangential component of acceleration is given by the formula:
tangential acceleration = (angular acceleration) * (distance from the center)
Substituting the known values, we have:
tangential acceleration = (-10.72) * 0.0813 ≈ -0.87 m/s²