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if the degree measure of an arc of a circle is increased by and the radius of the circle is increased by , by what percent does the length of the arc increase?

User Jim Lahman
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If the degree measure of an arc of a circle is increased by
\displaystyle x\% and the radius of the circle is increased by
\displaystyle y\%, we need to determine the percent by which the length of the arc increases.

Let's assume the original degree measure of the arc is
\displaystyle D, and the original radius of the circle is
\displaystyle R. The length of the arc is given by the formula:


\displaystyle \text{{Arc Length}}=2\pi R\left( \frac{{D}}{{360}}\right)

If the degree measure is increased by
\displaystyle x\%, the new degree measure would be
\displaystyle D+D\left( \frac{{x}}{{100}}\right) =D\left( 1+\frac{{x}}{{100}}\right).

If the radius is increased by
\displaystyle y\%, the new radius would be
\displaystyle R+R\left( \frac{{y}}{{100}}\right) =R\left( 1+\frac{{y}}{{100}}\right).

The new length of the arc, denoted as
\displaystyle L_{\text{{new}}}, can be calculated using the new degree measure and radius:


\displaystyle L_{\text{{new}}}=2\pi \left( R\left( 1+\frac{{y}}{{100}}\right)\right) \left( \frac{{D\left( 1+\frac{{x}}{{100}}\right)}}{{360}}\right)

To determine the percent increase in the length of the arc, we can calculate the percentage difference between the new length
\displaystyle L_{\text{{new}}} and the original length
\displaystyle L:


\displaystyle \text{{Percent Increase}}=\frac{{L_{\text{{new}}}-L}}{{L}}* 100

Now, we can substitute the expressions for
\displaystyle L_{\text{{new}}} and
\displaystyle L into the formula and simplify to determine the percent increase in the length of the arc.


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User Harshkn
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