Question

What is the length of the hypotenuse of right AUVW shown?

Answer 1

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Using Phythagoras Theorem:-

• ➙ (UW)² = (UV)² + (VW)²
• ➙ (x)² = (9)² + (40)²
• ➙ (x)² = (9 × 9) + (40 × 40)
• ➙ (x)² = (81) + (40 × 40)
• ➙ (x)² = 81 + 1600
• ➙ (x)² = 1681
• ➙ x = √1681
• ➙ x = √41 × 41
• ➙ x = 41

D) 41 ✅

Answer 2

D

Explanation:

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

UW² = UV² + VW²

x² = 9² + 40² = 81 + 1600 = 1681 ( take square root of both sides )

x =
`√(1681)` = 41

hypotenuse UW = 41