Final Answer:
b. 88.12 m The total distance traveled after the first bounce is the sum of the descent (16 meters) and the rise (12 meters), giving us a total of 28 meters.
Step-by-step explanation:
The total vertical distance traveled by the ball after the 10th bounce is 88.12 meters. This is calculated by adding the descending and ascending distances covered by the ball after each bounce.
In this scenario, the ball is dropped from a height of 16 meters. After the first bounce, it rises to 75% of its previous height (16 * 0.75 = 12 meters). The total distance traveled after the first bounce is the sum of the descent (16 meters) and the rise (12 meters), giving us a total of 28 meters.
For subsequent bounces, the ball continues this pattern: descending from the previous height and then rising to 75% of the previous height. After each bounce, the total distance traveled can be calculated by adding the descent and rise distances. By iteratively computing this for 10 bounces, the cumulative vertical distance traveled by the ball amounts to 88.12 meters.
The calculation considers both the initial descent and the subsequent rises and descents, leading to the conclusion that after the 10th bounce, the ball has covered a total vertical distance of 88.12 meters.