Question

Solve the equation. Please help

Answer 1

So, to solve the equation we want to isolate y or in other words, have y (alone) on one side so that we can find out what y should have as a value.

Step 1: Add 3/4 on both sides
We get
2y/3 = 1/12+3/4
We add fractions by calculating a common denominator, adjusting the numerators accordingly and adding them. See this in action below:
12 and 4 have a common multiple in 12 which will be our common denominator. Now, 1/12 does not need to be adjusted, but 3/4 becomes 3*3 / 3*4 = 9/12.
In total 1/12 + 9/12 = 10/12

So, we have 2y/3 = 10/12

Now we multiply both sides by 3, so that the 3 will cancel out the 3 in the denominator on the left side:
2y =30/12

Now we just need to divide by 2 and get the solution:
y = 15/12 = 3*5 / 3*4 = 5/4

Therefore the final answer is A:
The solution set is {5/4}

Answer 2

`\cfrac{2y}{3}-\cfrac{3}{4}=\cfrac{1}{12}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{2y}{3}-\cfrac{3}{4} \right)=12\left( \cfrac{1}{12} \right)}\implies 8y-9=1 \\\\\\ 8y=10\implies y=\cfrac{10}{8}\implies y=\cfrac{5}{4}`