Question

Help me solve this problem pelase

Answer 1

`A\approx 218.57\text{ cm}^2`

Explanation:

We can solve for the area of this isosceles triangle using Heron's formula:

`A = √(s(s-a)(s-b)^2)`

where
`a` is length of the base of the triangle,
`b` is the length of the two congruent sides, and
`s` is the triangle's semiperimeter (half-perimeter).

We can identify the following values from the given information:

• 
  `a = 14 \text{ cm}`
• 
  `b = 32\text{ cm}`
• 
  `\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---}\text{---} \\s = (14 + 32 + 32)/(2) = (78)/(2) = 39\text{ cm}`

Now, we can plug these values into the above area formula:

`A = √(s(s-a)(s-b)^2)`

`A = √(39(39-14)(39-32)^2)`

`A = √(39(25)(7)^2)`

`A = √(47,775)`

`A = 35√(39)`

`\boxed{A\approx 218.57\text{ cm}^2}`