Answer:
Solution Given:
C is the interest point of AD and EB.
AC ≅ EC and ∠A ≅ ∠E
To prove:
AB ≅ ED
Proof:
In ∆ABC and ∆EDC
∠BAC= ∠CED Given
AC = CE Given
∠ACB= ∠ECD Vertically opposite angle
∆ABC ≅ ∆EDC By ASA axiom
Therefore,
AB ≅ ED
Since the corresponding side and corresponding angle of a congruent triangles are congruent or equal.
Hence Proved: