Answer:
log₄(y√(x+1)/(16x))
Explanation:
You want −2−log₄x+1/2log₄(x+1)+log₄y as a single logarithm.
Rules of logarithms
The relevant rules of logarithms are ...
log(ab) = log(a) +log(b)
log(a/b) = log(a) -log(b)
log(a^b) = b·log(a)
Application
Writing the expression as a sum of logs, we have ...
log₄(4^(-2)) -log₄(x) +log₄(√(x+1)) +log₄(y)
= log₄(y√(x+1)/(16x))
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Additional comment
The only thing under the radical is (x+1).
The logarithm of the base is 1, so ...
log₄(4) = 1
-2 = -2·1 = -2·log₄(4) = log₄(4^-2)
This lets us use base 4 logarithms for everything.
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