Question

A slender rod with a length of 0.250 m rotates with an angular speed of 8.10 rad/s about an axis through one end and perpendicular to the rod. The plane of rotation of the rod is perpendicular to a uniform magnetic field with a magnitude of 0.600 T. What is the induced emf in the rod? Express your answer in volts. What is the potential difference between its ends? Express your answer in volts.

Answer 1

The induced emf in the rod is 1.215 volts. The potential difference between the ends of the rod is also 1.215 volts.

Step-by-step explanation:

When a rod rotates in a magnetic field, it experiences an induced emf, which is given by the equation:

emf = B * l * w

Where B is the magnetic field strength, l is the length of the rod, and w is the angular velocity.

In this case, the rod has a length of 0.250 m, an angular speed of 8.10 rad/s, and a magnetic field strength of 0.600 T. Plugging these values into the equation, we get:

emf = 0.600 T * 0.250 m * 8.10 rad/s = 1.215 V

So, the induced emf in the rod is 1.215 volts.

The potential difference between the ends of the rod is equal to the induced emf. Therefore, the potential difference between the ends of the rod is also 1.215 volts.