Question

Two identical discs sit at the bottom of a 3 m pool of

water whose surface is exposed to atmospheric pressure. The first disc acts as a plug to seal the drain as shown. The second disc covers a container containing nearly a perfect vacuum. If each disc has an area of 1 m', what is the
approximate difference in the force necessary to open the
containers? (Note: 1 atm = 101,300 Pa)

Answer 1

The approximate difference in force necessary to open the two containers can be calculated using the concept of pressure. Given that the discs are identical and have an area of 1 m² each, the force can be determined by multiplying the pressure difference by the area of each disc.

Step-by-step explanation:

The approximate difference in force necessary to open the two containers can be determined using the concept of pressure. The pressure exerted by a fluid is given by the formula:

P = F/A

Where P is the pressure, F is the force, and A is the area.

Since the two discs are identical and have an area of 1 m² each, the force necessary to open the containers can be calculated by multiplying the pressure by the area of each disc. The pressure is given by the difference in pressure between atmospheric pressure and the pressure inside the container:

ΔP = P(atm) - P(container)

Given that 1 atm is equal to 101,300 Pa, the force necessary to open the containers can be calculated as follows:

F = ΔP * A

F = (P(atm) - P(container)) * A

Substituting the values, we get:

F = (101,300 Pa - 0 Pa) * 1 m²

F = 101,300 N

Therefore, the approximate difference in force necessary to open the containers is 101,300 Newtons.