Explanation:
We can use trigonometry to solve this problem. Let's draw a diagram:
```
A - observer (1.5 m above ground)
B - base of the clock tower
C - top of the clock tower
D - intersection of AB and the horizontal ground
E - point on the ground directly below C
C
|
|
|
|
| x
|
|
|
-------------
|
|
|
|
|
|
|
|
|
B
|
|
|
|
|
|
|
|
|
|
|
A
```
We want to find the height of the clock tower, which is CE. We have the angle of elevation ACD, which is 19 degrees, and the distance AB, which is 100 m. We can use tangent to find CE:
tan(ACD) = CE / AB
tan(19) = CE / 100
CE = 100 * tan(19)
CE ≈ 34.5 m (rounded to 1 decimal place)
Therefore, the height of the clock tower is approximately 34.5 m.