Answer:
zeroes of the equations are x= 1 , -3
Explanation:
firstly divide both sides by 2 so new equation will be
x^2+2x-3=0
you can use quadratic formula or simply factor it
its factors will be
x^2 +3x - x -3=0
(x+3)(x-1)=0
are two factors
so
either
x+3=0 or x-1=0
x=-3 and x=1
so zeroes of the equations are x= 1 , -3
by the way you can also use quadratic formula which is
[-b+-(b^2 -4ac)]/2a
where a is coefficient of x^2 and b is coefficient of x
and c is constant term