Answer:
First, we need to find out how many moles of BaBr2 we have. We can do this by dividing the given mass by its molar mass:
Moles of BaBr2 = 272.08 g / 297.13 g/mol = 0.915 moles
From the balanced equation, we know that 1 mole of BaBr2 reacts with 2 moles of KBr. Therefore, we can use stoichiometry to find out how many moles of KBr will be produced:
Moles of KBr = 0.915 moles BaBr2 × (2 moles KBr / 1 mole BaBr2) = 1.83 moles KBr
Finally, we can use the molar mass of KBr to calculate its mass:
Mass of KBr = 1.83 moles × 119.00 g/mol = 217.77 g
Therefore, 272.08 grams of BaBr2 will produce 217.77 grams or 1.83 moles of KBr.