Solve for all values of x by factoring x^2+21x+50=6x

Question 1

Solve for all values of x by factoring
x^2+21x+50=6x

Question 2

$\sf \longrightarrow \: {x}^(2) + 21x + 50 = 6x$

$\sf \longrightarrow \: {x}^(2) + 21x - 6x+ 50 =0$

$\sf \longrightarrow \: {x}^(2) + 15x+ 50 =0$

$\sf \longrightarrow \: {x}^(2) + 10x + 5x+ 50 =0$

$\sf \longrightarrow \: x(x + 10) + 5(x + 10) =0$

$\sf \longrightarrow \: (x + 10) (x + 5) =0$

$\sf \longrightarrow \: (x + 10) = 0 \qquad \: and \: \qquad(x + 5) =0$

$\sf \longrightarrow \: x + 10 = 0 \qquad \: and \: \qquad \: x + 5=0$

$\sf \longrightarrow \: x = 0 - 10\qquad \: and \: \qquad \: x = 0 - 5$

$\sf \longrightarrow \: x =-10 \qquad \: and \: \qquad \: x = - 5$

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