Answer:
Na2SO4= 0.04mol/L
Na3PO4=0.07mol/L
Li2SO4=0.02mol/L
Mol/L= M or Molarity
Step-by-step explanation:
Step 1
Find the molar mass for each compound (molar mass unit is g/mol and is equal to the mass number present on the element)
Na2SO4 = 142g/mol
Na2= (23*2)=46g/mol
S=32g/mol
O3=(16*4)=64g/mol
Hence, 46+32+64=142 g/mol
Na3PO4= 164g/mol
Li2SO4=110g/mol
Step 2
Using the molar mass determine the mols of each compound. (mol=g/molar mass)
Na2SO4 = 0.004mol
0.53g/142gmol
=0.00373mol
=0.004mol
Na3PO4= 0.007
Li2SO4=0.002
Step 3
Calculate the Molarity (mol/L)
Na2SO4= 0.04mol/L
100mL/1000= 0.1L
NB Molarity is always in the units mol/L hence we must convert mL into L
0.004/0.1
=0.04mol/L
Na3PO4= 0.07mol/L
Li2SO4=0.02mol/L