Answer:
(3x + 1)(2x - 5)
Explanation:
6x² - 13x - 5
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term , that is
product = 6 × - 5 = - 30 and sum = - 13
the factors are + 2 and - 15
use these factors to split the x- term
6x² + 2x - 15x - 5 ( factor the first/second and third/fourth terms )
= 2x(3x + 1) - 5(3x + 1) ← factor out (3x + 1) from each term
= (3x + 1)(2x - 5) ← in factored form