Question

Graph a line that contains the point (-5,-3) (−5,−3) with a slope of -2

What's the answer please help??

Answer 1

See below and attached graph.

Explanation:

The slope-intercept form of a straight line equation is y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).

With a slope of -2, we can write:

y = -2x + b

To find b, enter the given point (-5,-3) and solve for b:

y = -2x + b

-3 = -2(-5) + b

-3 = 10 + b

b = -13

The equation becomes: y = -2x -13

See the attached graph.