Question

A rifle is fired straight up, and the bullet leaves the rifle with an initial velocity

magnitude of 630 m/s. After 5.00 s, the velocity is 581 m/s. At what rate is the bullet
decelerated?

Answer 1

Step-by-step explanation:

acceleration definition = change in velocity / change in time =

(630 - 581) m/s / 5 s = 49 / 5 = 9.8 m/s^2 was the deceleration