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Cuánto es x al cuadrado menos 6x + 8 = 0


User Kijewski
by
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1 Answer

6 votes

Answer:

the solutions to the equation x^2 - 6x + 8 = 0 are x = 4 and x = 2.

Explanation:

To find the value of x in the equation x^2 - 6x + 8 = 0, we can use the quadratic formula, which is given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

For this equation, a = 1, b = -6, and c = 8. Substituting these values into the quadratic formula, we get:

x = (-(-6) ± √((-6)^2 - 4(1)(8))) / (2(1))

= (6 ± √(36 - 32)) / 2

= (6 ± √4) / 2

= (6 ± 2) / 2

This gives us two possible solutions:

x = (6 + 2) / 2 = 8 / 2 = 4

x = (6 - 2) / 2 = 4 / 2 = 2

Therefore, the solutions to the equation x^2 - 6x + 8 = 0 are x = 4 and x = 2.

User Simonthumper
by
9.5k points

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