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A firm produces three sizes of similar-shaped labels for its products. Their areas are 150 cm²,

250 cm² and 400 cm².
The 250 cm² label fits around a can of height 8 cm. Find the heights of similar cans around
which the other two labels would fit.

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Answer:

Denote the height of the can corresponding to the 150 cm² label as h₁ and the height of the can corresponding to the 400 cm² label as h₂.

We know that the area of a label is equal to the circumference of the can multiplied by its height.

For the 250 cm² label:

Area = 250 cm²

Circumference = 250 cm² / 8 cm = 31.25 cm (since circumference = Area / height)

Height = 8 cm (given)

For the 150 cm² label:

Area = 150 cm²

Circumference = 150 cm² / h₁

Height = h₁ (to be determined)

For the 400 cm² label:

Area = 400 cm²

Circumference = 400 cm² / h₂

Height = h₂ (to be determined)

Since the labels are similar in shape, the ratios of their corresponding measurements (heights and circumferences) will be the same.

Setting up the proportions:

250 cm² / 8 cm = 150 cm² / h₁ = 400 cm² / h₂

To find h₁, we can solve the second ratio:

150 cm² / h₁ = 250 cm² / 8 cm

Cross-multiplying:

150 cm² * 8 cm = 250 cm² * h₁

1200 cm² = 250 cm² * h₁

Dividing both sides by 250 cm²:

1200 cm² / 250 cm² = h₁

h₁ ≈ 4.8 cm

Therefore, the height of the can that the 150 cm² label would fit around is approximately 4.8 cm.

To find h₂, we can solve the third ratio:

400 cm² / h₂ = 250 cm² / 8 cm

Cross-multiplying:

400 cm² * 8 cm = 250 cm² * h₂

3200 cm² = 250 cm² * h₂

Dividing both sides by 250 cm²:

3200 cm² / 250 cm² = h₂

h₂ ≈ 12.8 cm

The height of the can that the 400 cm² label would fit around is approximately 12.8 cm.

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