Question

In python Which would be the base case in a recursive solution to the problem of finding the factorial of a number. Recall that the factorial of a non-negative whole number is defined as n! where:

If n = 0, then n! = 1
If n > 0, then n! = 1 x 2 x 3 x ... x n
n = 1
n > 0
n = 0
The factorial of a number cannot be solved with recursion.

Answer 1

def factorial(n):

if n == 0:

return 1

else:

return n * factorial(n-1)

Step-by-step explanation:

In a recursive solution to finding the factorial of a number, the base case would be when n is equal to 0. This is because the factorial of 0 is defined as 1, and this is the value that will be returned when the recursive function encounters this base case.In this function, the base case is when n is equal to 0. When the function is called with an n value of 0, it returns 1 and the recursion ends. If n is greater than 0, the function returns n multiplied by the result of calling the factorial function with an n value of n-1. This process continues until the base case is reached, at which point the recursion ends and the final result is returned.

For example, if you call factorial(5), the function would return 120, which is the factorial of 5. The function would compute this result by first calling itself with an n value of 4, then with an n value of 3, and so on, until it reaches the base case of n equal to 0.