Answer:
1) AB ~ EF, BC ~ FG, CD ~ GH, AD ~ EH
2) Angle A is congruent to angle E.
Angle B is congruent to angle F.
Angle C is congruent to angle G.
Angle D is congruent to angle H.
3) AD = BC = 8, CD = (2/3)(6) = 4, so
AB = 3(4) = 12, EF = (3/2)(12) = 18,
EH = FG = (2/3)(8) = 12
Perimeter of ABCD = 12 + 8 + 8 + 4
= 32 cm
Perimeter of EFGH = 18 + 12 + 12 + 6
= 48 cm