Question

Please help i’ll give 20 points

Answer 1

E

Explanation

`√(3-2x)` =
`√(2x)` + 1

square both sides to clear the radicals

(
`√(3-2x)` )² = (
`√(2x)` + 1)²← expand using FOIL

3 - 2x = 2x + 2
`√(2x)` + 1 ( subtract 2x + 1 from both sides )

- 4x + 2 = 2
`√(2x)` ( divide through by 2 )

- 2x + 1 =
`√(2x)` ( square both sides )

(- 2x + 1)² = 2x ← expand left side using FOIL

4x² - 4x + 1 = 2x ( add 4x to both sides )

4x² + 1 = 6x ( subtract 1 from both sides )

4x² = 6x - 1