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find f(x) given that it is a third degree polynomial equation with roots x = 0,6,-5, and the coefficient of the x' term is 2.

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We know that the polynomial has roots at x=0, x=6, and x=-5. We can express the polynomial as a product of linear factors using these roots:
```
f(x) = a(x-0)(x-6)(x+5)
```
where `a` is a constant. Since we know that the coefficient of the `x^3` term is 2, we can set `a` such that this is the case:
```
f(x) = 2(x-0)(x-6)(x+5)
```
We can simplify and multiply this out to get the final form of `f(x)`:
```
f(x) = 2(x^3 - x^2 - 30x)
f(x) = 2x^3 - 2x^2 - 60x
```

Therefore, the third degree polynomial equation with roots x = 0,6,-5, and the coefficient of the x^2 term is 2, is `f(x) = 2x^3 - 2x^2 - 60x`.
User Tylerweir
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