To find the amount of heat released when burning 0.162 mol of the solid in the bomb calorimeter, we can use the concept of heat capacity and the equation:
q = C * ΔT
where:
q is the heat transferred (in joules),
C is the heat capacity of the bomb calorimeter (in joules per Kelvin),
ΔT is the change in temperature (in Kelvin).
First, let's calculate the heat released when burning 2.465 g of the solid:
First, convert the mass of the solid to moles:
moles = mass / molar mass
moles = 2.465 g / 551.2 g/mol
moles = 0.00447 mol
Now, let's calculate the heat released for this amount of solid burned:
q1 = C * ΔT
q1 = 555 J/K * 2.22 K
q1 = 1232.1 J
Now, let's find the heat released per mole of the solid:
q per mole = q1 / 0.00447 mol
q per mole = 1232.1 J / 0.00447 mol
q per mole = 275,695 J/mol
Finally, let's find the heat released when burning 0.162 mol of the solid:
q2 = q per mole * 0.162 mol
q2 = 275,695 J/mol * 0.162 mol
q2 = 44,697 J
Converting the heat released to kilojoules:
q2_kJ = q2 / 1000
q2_kJ = 44,697 J / 1000
q2_kJ = 44.697 kJ
Therefore, if we were to burn 0.162 mol of the solid in the bomb calorimeter, approximately 44.697 kJ of heat would be released.