Question

Now separate out the four single, crossed-over chromosomes to model four haploid cells from each parent.

Next, make at least four genetic matches of offspring by moving a chromosome from a sperm and egg cell together to form a diploid offspring. In the table, record the genotype and phenotype of each offspring as shown in the example.


Genotype (genes inherited)Phenotype (outward traits)Offspring 1

Offspring 2

Offspring 3

Offspring 4

Answer 1

Step-by-step explanation:

To separate out the four single, crossed-over chromosomes, we'll assume that each parent has two pairs of chromosomes, labeled A/a and B/b, respectively. We'll denote the maternal chromosomes as MA and MB, and the paternal chromosomes as PA and PB. The crossover event occurs between the A and B chromosomes.

Let's create four haploid cells from each parent by randomly selecting one of the two alleles from each chromosome:

Parent 1 (Maternal):

- Haploid cell 1 (MA): A

- Haploid cell 2 (MB): a

Parent 2 (Paternal):

- Haploid cell 3 (PA): B

- Haploid cell 4 (PB): b

Now, let's make the genetic matches by combining one haploid cell from the sperm and one from the egg to form a diploid offspring:

Offspring 1: MA + PA

- Genotype: A + B

- Phenotype: AB (combining the traits from both alleles)

Offspring 2: MB + PA

- Genotype: a + B

- Phenotype: aB (expressing the trait associated with the B allele)

Offspring 3: MA + PB

- Genotype: A + b

- Phenotype: Ab (expressing the trait associated with the A allele)

Offspring 4: MB + PB

- Genotype: a + b

- Phenotype: ab (expressing neither of the traits associated with A or B alleles)

Please note that the genotypes and phenotypes provided here are based on the hypothetical scenario described and may not correspond to actual traits or genetic outcomes.